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5u^2+55u+120=0
a = 5; b = 55; c = +120;
Δ = b2-4ac
Δ = 552-4·5·120
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{625}=25$$u_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(55)-25}{2*5}=\frac{-80}{10} =-8 $$u_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(55)+25}{2*5}=\frac{-30}{10} =-3 $
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